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48.
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Given: A one-family dwelling to be built will have 4,000 sq. ft. of livable space, a 600 sq. ft. garage, a 400 sq. ft. open porch, a 2,000 sq. ft. unfinished basement (adaptable for future use), three (3) small-appliance branch-circuits and a branch circuit for the laundry room. Determine the demand load, in VA, on the ungrounded service-entrance conductors for the general lighting and receptacle loads using the standard method of calculation for a one-family dwelling.
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To solve this problem take into consideration the following related information
regarding calculations for dwelling units:
1) According to Section 220.12, a unit load of 3 VA as specified in Table 220.12 shall constitute the minimum lighting load. The calculation floor area shall not include garages and open porches.
2) As per Section 220.52(A), each small appliance circuit shall be calculated at 1,500 VA each.
3) Section 220.52(B) specifies a load of not less than 1,500 VA is to be included for the laundry branch circuit.
4) As permitted by Section 220.42, the demand factors specified in Table 220.42 shall apply to that portion of the total branch circuit load calculated for general illumination.
Therefore, to calculate the demand load do the math as follows.
4,000 sq. ft. + 2,000 sq. ft. = 6,000 sq. ft. x 3 VA = 18,000 VA
three small appliance circuits @ 1,500 VA each = 4,500 VA
one laundry circuit @ 1,500 VA = 1,500 VA
Total connected load = 24,000 VA
1st 3,000 VA @ 100% 3,000 VA
24,000 VA - 3,000 VA = 21,000 VA (remainder) @ 35% = 7,350 VA
Total demand load = 10,350 VA
Incorrect answer. Please choose another answer.
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To solve this problem take into consideration the following related information
regarding calculations for dwelling units:
1) According to Section 220.12, a unit load of 3 VA as specified in Table 220.12 shall constitute the minimum lighting load. The calculation floor area shall not include garages and open porches.
2) As per Section 220.52(A), each small appliance circuit shall be calculated at 1,500 VA each.
3) Section 220.52(B) specifies a load of not less than 1,500 VA is to be included for the laundry branch circuit.
4) As permitted by Section 220.42, the demand factors specified in Table 220.42 shall apply to that portion of the total branch circuit load calculated for general illumination.
Therefore, to calculate the demand load do the math as follows.
4,000 sq. ft. + 2,000 sq. ft. = 6,000 sq. ft. x 3 VA = 18,000 VA
three small appliance circuits @ 1,500 VA each = 4,500 VA
one laundry circuit @ 1,500 VA = 1,500 VA
Total connected load = 24,000 VA
1st 3,000 VA @ 100% 3,000 VA
24,000 VA - 3,000 VA = 21,000 VA (remainder) @ 35% = 7,350 VA
Total demand load = 10,350 VA
Incorrect answer. Please choose another answer.
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|
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To solve this problem take into consideration the following related information
regarding calculations for dwelling units:
1) According to Section 220.12, a unit load of 3 VA as specified in Table 220.12 shall constitute the minimum lighting load. The calculation floor area shall not include garages and open porches.
2) As per Section 220.52(A), each small appliance circuit shall be calculated at 1,500 VA each.
3) Section 220.52(B) specifies a load of not less than 1,500 VA is to be included for the laundry branch circuit.
4) As permitted by Section 220.42, the demand factors specified in Table 220.42 shall apply to that portion of the total branch circuit load calculated for general illumination.
Therefore, to calculate the demand load do the math as follows.
4,000 sq. ft. + 2,000 sq. ft. = 6,000 sq. ft. x 3 VA = 18,000 VA
three small appliance circuits @ 1,500 VA each = 4,500 VA
one laundry circuit @ 1,500 VA = 1,500 VA
Total connected load = 24,000 VA
1st 3,000 VA @ 100% 3,000 VA
24,000 VA - 3,000 VA = 21,000 VA (remainder) @ 35% = 7,350 VA
Total demand load = 10,350 VA
Incorrect answer. Please choose another answer.
|
|
|
|
|
To solve this problem take into consideration the following related information
regarding calculations for dwelling units:
1) According to Section 220.12, a unit load of 3 VA as specified in Table 220.12 shall constitute the minimum lighting load. The calculation floor area shall not include garages and open porches.
2) As per Section 220.52(A), each small appliance circuit shall be calculated at 1,500 VA each.
3) Section 220.52(B) specifies a load of not less than 1,500 VA is to be included for the laundry branch circuit.
4) As permitted by Section 220.42, the demand factors specified in Table 220.42 shall apply to that portion of the total branch circuit load calculated for general illumination.
Therefore, to calculate the demand load do the math as follows.
4,000 sq. ft. + 2,000 sq. ft. = 6,000 sq. ft. x 3 VA = 18,000 VA
three small appliance circuits @ 1,500 VA each = 4,500 VA
one laundry circuit @ 1,500 VA = 1,500 VA
Total connected load = 24,000 VA
1st 3,000 VA @ 100% 3,000 VA
24,000 VA - 3,000 VA = 21,000 VA (remainder) @ 35% = 7,350 VA
Total demand load = 10,350 VA
Incorrect answer. Please choose another answer.
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